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← JEE Advanced 2022 · Paper 2
MathematicsSingle correct+3 / -1Question 15 of 54

JEE Advanced 2022 · Paper 2, Mathematics question 15

Consider 4 boxes, where each box contains 3 red balls and 2 blue balls. Assume that all 20 balls are distinct. In how many different ways can 10 balls be chosen from these 4 boxes so that from each box at least one red ball and one blue ball are chosen?

Choose one option
Answer and worked solution

Official answer: A

Ways to take kk balls from one box (3 red, 2 blue) with at least one of each colour:

  • k=2k=2: 3⋅2=63\cdot2=6.
  • k=3k=3: (53)−(33)=9\binom53-\binom33=9 (remove the all-red choice).
  • k=4k=4: (54)=5\binom54=5 (four balls always include both colours).

Split the 10 balls. Each box gives at least 2, which leaves 2 extra.

  • One box takes 4: 4⋅5⋅63=43204\cdot5\cdot6^3=4320.
  • Two boxes take 3: (42)⋅92⋅62=17496\binom42\cdot9^2\cdot6^2=17496.

Total. 4320+17496=218164320+17496=21816. (A).