Skip to content
dronacharya.ai
← JEE Advanced 2022 · Paper 1
PhysicsNumerical+3Question 26 of 54

JEE Advanced 2022 · Paper 1, Physics question 8

A projectile is fired from horizontal ground with speed vv and projection angle θ\theta. When the acceleration due to gravity is gg, the range of the projectile is dd. If at the highest point in its trajectory, the projectile enters a different region where the effective acceleration due to gravity is g′=g0.81g' = \dfrac{g}{0.81}, then the new range is d′=ndd' = nd. The value of nn is _____.

Answer and worked solution

Official answer: 0.93

First half. Up to the highest point the projectile covers d2\frac d2 horizontally.

Second half. From the top it falls a height HH from rest vertically. The fall time is 2H/g′\sqrt{2H/g'}, which is 0.81=0.9\sqrt{0.81}=0.9 of the original fall time, so it covers 0.9⋅d20.9\cdot\frac d2.

d′=d2+0.45d=0.95d  ⟹  n=0.95.d'=\frac d2+0.45d=0.95d\implies n=0.95.