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← JEE Advanced 2022 · Paper 1
PhysicsNumerical+3Question 21 of 54

JEE Advanced 2022 · Paper 1, Physics question 3

In the following circuit C1=12 μFC_1 = 12\ \mu F, C2=C3=4 μFC_2 = C_3 = 4\ \mu F and C4=C5=2 μFC_4 = C_5 = 2\ \mu F. The charge stored in C3C_3 is _____ μC\mu C.

A 6 V battery forms the left side; its top terminal connects through C1 (along the top wire) to a junction T. From T, capacitors C2, C3, C4 and C5 each run down to the common bottom wire, which also joins the bottom of the 6 V battery. A 2 V battery on the right side is connected between the top wire at T and the bottom wire, so C2, C3, C4 and C5 are all directly across the 2 V battery.
Answer and worked solution

Official answer: 7.9

Follow the wiring. C2C_2, C3C_3, C4C_4 and C5C_5 all join the top junction to the bottom wire. The 2 V battery joins the same two points, so each of these capacitors has exactly 2 V across it. (C1C_1 and the 6 V battery form a separate loop.)

Q3=C3V=4 μF×2 V=8 μC.Q_3=C_3V=4\ \mu F\times2\ V=8\ \mu C.