Skip to content
dronacharya.ai
← JEE Advanced 2022 · Paper 1
MathematicsMultiple correct+4 / -2Question 13 of 54

JEE Advanced 2022 · Paper 1, Mathematics question 13

Consider the parabola y2=4xy^2 = 4x. Let SS be the focus of the parabola. A pair of tangents drawn to the parabola from the point P=(−2,1)P = (-2, 1) meet the parabola at P1P_1 and P2P_2. Let Q1Q_1 and Q2Q_2 be points on the lines SP1SP_1 and SP2SP_2 respectively such that PQ1PQ_1 is perpendicular to SP1SP_1 and PQ2PQ_2 is perpendicular to SP2SP_2. Then, which of the following is/are TRUE?

Choose one or more options
Answer and worked solution

Official answer: B, C, D

Points of contact. The focus is S=(1,0)S=(1,0). A tangent y=mx+1my=mx+\frac1m through P(−2,1)P(-2,1) needs 2m2+m−1=02m^2+m-1=0, so m=12m=\frac12 or −1-1. The points of contact (1m2,2m)\left(\frac1{m^2},\frac2m\right) are (4,4)(4,4) and (1,−2)(1,-2).

Line through (4, 4). SS to (4,4)(4,4) has unit direction (35,45)(\frac35,\frac45), and P−S=(−3,1)P-S=(-3,1).

  • Projection: SQ=∣(−3)35+1⋅45∣=1SQ=|(-3)\tfrac35+1\cdot\tfrac45|=1.
  • Perpendicular: PQ=3PQ=3.
  • Foot: Q=(25,−45)Q=(\frac25,-\frac45).

Line through (1, −2). This is x=1x=1, so the foot is Q=(1,1)Q=(1,1), with SQ=1SQ=1 and PQ=3PQ=3.

Options. Whichever point is called P1P_1:

  • SQ1=SQ2=1SQ_1=SQ_2=1, so (A) is false and (D) is true.
  • PQ1=3PQ_1=3, so (C) is true.
  • Q1Q2=(35)2+(95)2=3105Q_1Q_2=\sqrt{(\frac35)^2+(\frac95)^2}=\frac{3\sqrt{10}}5, so (B) is true.