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← JEE Advanced 2021 · Paper 2
PhysicsNumerical+2Question 9 of 57

JEE Advanced 2021 · Paper 2, Physics question 9

Passage

Question Stem for Question Nos. 9 and 10

A pendulum consists of a bob of mass m=0.1m = 0.1 kg and a massless inextensible string of length L=1.0L = 1.0 m. It is suspended from a fixed point at height H=0.9H = 0.9 m above a frictionless horizontal floor. Initially, the bob of the pendulum is lying on the floor at rest vertically below the point of suspension. A horizontal impulse P=0.2P = 0.2 kg-m/s is imparted to the bob at some instant. After the bob slides for some distance, the string becomes taut and the bob lifts off the floor. The magnitude of the angular momentum of the pendulum about the point of suspension just before the bob lifts off is JJ kg-m2^2/s. The kinetic energy of the pendulum just after the lift-off is KK Joules.

The value of JJ is ____.

Answer and worked solution

Official answer: 0.16

After the impulse. The bob moves horizontally at v=Pm=2v=\frac Pm=2 m/s along the floor. The string is slack until it becomes taut.

Angular momentum about the suspension point. The velocity is horizontal, and the suspension point is H=0.9H=0.9 m above the floor. So, just before lift-off,
J=mvH=0.1×2×0.9=0.18 kg m2/s.J=mvH=0.1\times2\times0.9=0.18\text{ kg m}^2/\text{s}.