Skip to content
dronacharya.ai
← JEE Advanced 2021 · Paper 2
PhysicsMultiple correct+4 / -2Question 1 of 57

JEE Advanced 2021 · Paper 2, Physics question 1

One end of a horizontal uniform beam of weight WW and length LL is hinged on a vertical wall at point OO and its other end is supported by a light inextensible rope. The other end of the rope is fixed at point QQ, at a height LL above the hinge at point OO. A block of weight αW\alpha W is attached at the point PP of the beam, as shown in the figure (not to scale). The rope can sustain a maximum tension of (22)W(2\sqrt2)W. Which of the following statement(s) is(are) correct?

A horizontal beam OP of length L and weight W hinged at O on a vertical wall. A rope runs from the free end P up to point Q on the wall, a height L above O (so the rope makes 45° with the beam). A block of weight αW hangs from P.
Choose one or more options
Answer and worked solution

Official answer: A, B, D

Torque about the hinge O. The rope runs from P to Q, which is LL above O, so it makes 45∘45^\circ with the beam:
Tsin⁡45∘ L=WL2+αWL  ⟹  T=2 W(12+α).T\sin45^\circ\,L=W\frac L2+\alpha WL\implies T=\sqrt2\,W\left(\tfrac12+\alpha\right).

Force balance. The rope pulls with horizontal and vertical components Tcos⁡45∘=Tsin⁡45∘=W(12+α)T\cos45^\circ=T\sin45^\circ=W\left(\frac12+\alpha\right).

  • Horizontal reaction at O: H=W(12+α)H=W\left(\frac12+\alpha\right).
  • Vertical reaction at O: V=W+αW−W(12+α)=W2V=W+\alpha W-W\left(\frac12+\alpha\right)=\frac W2.

Check each option.

  • (A) V=W2V=\frac W2 does not depend on α\alpha. True.
  • (B) For α=0.5\alpha=0.5, H=WH=W. True.
  • (C) For α=0.5\alpha=0.5, T=2WT=\sqrt2W, not 2W2W. False.
  • (D) The rope breaks when T>22WT>2\sqrt2W, i.e. 12+α>2\frac12+\alpha>2, i.e. α>1.5\alpha>1.5. True.

(A), (B), (D)