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MathematicsInteger+4Question 56 of 57

JEE Advanced 2021 · Paper 2, Mathematics question 18

Let EE be the ellipse x216+y29=1\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1. For any three distinct points PP, QQ and Q′Q' on EE, let M(P,Q)M(P, Q) be the mid-point of the line segment joining PP and QQ, and M(P,Q′)M(P, Q') be the mid-point of the line segment joining PP and Q′Q'. Then the maximum possible value of the distance between M(P,Q)M(P, Q) and M(P,Q′)M(P, Q'), as PP, QQ and Q′Q' vary on EE, is ____.

Answer and worked solution

Official answer: 4

Distance between the midpoints.
M(P,Q)−M(P,Q′)=(P+Q)−(P+Q′)2=Q−Q′2,M(P,Q)-M(P,Q')=\frac{(P+Q)-(P+Q')}2=\frac{Q-Q'}2,
so the distance is 12∣QQ′∣\frac12|QQ'|.

Maximise. The longest chord of the ellipse is the major axis, of length 8, and PP can be any third point. The maximum distance is 4.