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← JEE Advanced 2021 · Paper 1
PhysicsMultiple correct+4 / -2Question 11 of 57

JEE Advanced 2021 · Paper 1, Physics question 11

A horizontal force FF is applied at the center of mass of a cylindrical object of mass mm and radius RR, perpendicular to its axis as shown in the figure. The coefficient of friction between the object and the ground is μ\mu. The center of mass of the object has an acceleration aa. The acceleration due to gravity is gg. Given that the object rolls without slipping, which of the following statement(s) is(are) correct?

A cylinder (circle of radius R, radius drawn dashed) resting on horizontal ground, with a horizontal force F applied at its centre, pointing to the right.
Choose one or more options
Answer and worked solution

Official answer: B, D

Rolling equations. For rolling without slipping, with friction ff opposing the motion:
F−f=ma,fR=IaR  ⟹  a=Fm+I/R2,f=IR2a.F-f=ma,\qquad fR=I\frac aR\implies a=\frac{F}{m+I/R^2},\qquad f=\frac{I}{R^2}a.

Check each option.

  • (A) aa depends on II, which differs for solid and hollow cylinders. False.
  • (B) For a solid cylinder I=12mR2I=\frac12mR^2, so f=ma2f=\frac{ma}2. Requiring f≤μmgf\le\mu mg gives a≤2μga\le2\mu g. True.
  • (C) Static friction only takes whatever value is needed; it is not always μmg\mu mg. False.
  • (D) For a thin-walled cylinder I=mR2I=mR^2, so a=F2ma=\frac F{2m}. True.

(B), (D)