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← JEE Advanced 2021 · Paper 1
MathematicsMultiple correct+4 / -2Question 51 of 57

JEE Advanced 2021 · Paper 1, Mathematics question 13

Let EE, FF and GG be three events having probabilities
P(E)=18,P(F)=16andP(G)=14,and let P(E∩F∩G)=110.P(E) = \frac18,\quad P(F) = \frac16\quad\text{and}\quad P(G) = \frac14,\quad\text{and let } P(E\cap F\cap G) = \frac1{10}.
For any event HH, if HcH^c denotes its complement, then which of the following statements is (are) TRUE?

Choose one or more options
Answer and worked solution

Official answer: A, B, C

Check each option. Each pairwise intersection is at least P(E∩F∩G)=110P(E\cap F\cap G)=\frac1{10}.

  • (A) P(E∩F∩Gc)=P(E∩F)−110≤18−110=140P(E\cap F\cap G^c)=P(E\cap F)-\frac1{10}\le\frac18-\frac1{10}=\frac1{40}. True.
  • (B) P(Ec∩F∩G)≤P(F)−110=115P(E^c\cap F\cap G)\le P(F)-\frac1{10}=\frac1{15}. True.
  • (C) By inclusion-exclusion,
    P(E∪F∪G)≤18+16+14−310+110=41120≤1324.P(E\cup F\cup G)\le\frac18+\frac16+\frac14-\frac3{10}+\frac1{10}=\frac{41}{120}\le\frac{13}{24}.
    True.
  • (D) P(Ec∩Fc∩Gc)=1−P(E∪F∪G)≥79120>512P(E^c\cap F^c\cap G^c)=1-P(E\cup F\cup G)\ge\frac{79}{120}>\frac5{12}. False.

(A), (B), (C)