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← JEE Advanced 2021 · Paper 1
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JEE Advanced 2021 · Paper 1, Mathematics question 7

Passage

Question Stem for Question Nos. 7 and 8

Let α\alpha, β\beta and γ\gamma be real numbers such that the system of linear equations
x+2y+3z=α4x+5y+6z=β7x+8y+9z=γ−1\begin{aligned}x + 2y + 3z &= \alpha\\ 4x + 5y + 6z &= \beta\\ 7x + 8y + 9z &= \gamma - 1\end{aligned}
is consistent. Let ∣M∣|M| represent the determinant of the matrix
M=[α2γβ10−101]M = \begin{bmatrix}\alpha & 2 & \gamma\\ \beta & 1 & 0\\ -1 & 0 & 1\end{bmatrix}
Let PP be the plane containing all those (α,β,γ)(\alpha, \beta, \gamma) for which the above system of linear equations is consistent, and DD be the square of the distance of the point (0,1,0)(0, 1, 0) from the plane PP.

The value of ∣M∣|M| is ____.

Answer and worked solution

Official answer: 0.95

Consistency. The coefficient rows satisfy R1−2R2+R3=0R_1-2R_2+R_3=0, so the matrix is singular. The system is consistent exactly when the right-hand sides satisfy the same relation:
α−2β+(γ−1)=0  ⟹  α−2β+γ=1.\alpha-2\beta+(\gamma-1)=0\implies\alpha-2\beta+\gamma=1.

The determinant. Expanding along the first row:
∣M∣=α(1)−2(β)+γ(1)=α−2β+γ=1.|M|=\alpha(1)-2(\beta)+\gamma(1)=\alpha-2\beta+\gamma=1.