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← JEE Advanced 2021 · Paper 1
MathematicsSingle correct+3 / -1Question 39 of 57

JEE Advanced 2021 · Paper 1, Mathematics question 1

Consider a triangle Δ\Delta whose two sides lie on the xx-axis and the line x+y+1=0x + y + 1 = 0. If the orthocenter of Δ\Delta is (1,1)(1, 1), then the equation of the circle passing through the vertices of the triangle Δ\Delta is

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Answer and worked solution

Official answer: B

Vertices. One vertex is where the two given sides meet: A=(−1,0)A=(-1,0). Let BB be the other vertex on the xx-axis and CC the other vertex on x+y+1=0x+y+1=0.

  • The altitude from CC is perpendicular to the xx-axis and passes through H=(1,1)H=(1,1), so it is x=1x=1. Then C=(1,−2)C=(1,-2).
  • The altitude from BB is perpendicular to x+y+1=0x+y+1=0 and passes through HH, so it is y=xy=x. Then B=(0,0)B=(0,0).

Circle. Since it passes through the origin, write it as x2+y2+2gx+2fy=0x^2+y^2+2gx+2fy=0.

  • At (−1,0)(-1,0): 1−2g=01-2g=0, so g=12g=\frac12.
  • At (1,−2)(1,-2): 5+1−4f=05+1-4f=0, so f=32f=\frac32.

The circle is x2+y2+x+3y=0x^2+y^2+x+3y=0. (B)