JEE Advanced 2021 · Paper 1, Chemistry question 9

Question Stem for Question Nos. 9 and 10

The boiling point of water in a 0.1 molal silver nitrate solution (solution $\mathbf A$) is $\mathbf x$ °C. To this solution $\mathbf A$, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution $\mathbf B$. The difference in the boiling points of water in the two solutions $\mathbf A$ and $\mathbf B$ is $\mathbf y \times 10^{-2}$ °C.

(Assume: Densities of the solutions $\mathbf A$ and $\mathbf B$ are the same as that of water and the soluble salts dissociate completely.

Use: Molal elevation constant (Ebullioscopic Constant), $K_b = 0.5$ K kg mol$^{-1}$; Boiling point of pure water as 100 °C.)