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← JEE Advanced 2020 · Paper 2
MathematicsMultiple correct+4 / -2Question 47 of 54

JEE Advanced 2020 · Paper 2, Mathematics question 11

Let aa and bb be positive real numbers. Suppose PQ→=ai^+bj^\overrightarrow{PQ} = a\hat i + b\hat j and PS→=ai^−bj^\overrightarrow{PS} = a\hat i - b\hat j are adjacent sides of a parallelogram PQRSPQRS. Let u⃗\vec u and v⃗\vec v be the projection vectors of w⃗=i^+j^\vec w = \hat i + \hat j along PQ→\overrightarrow{PQ} and PS→\overrightarrow{PS}, respectively. If ∣u⃗∣+∣v⃗∣=∣w⃗∣|\vec u| + |\vec v| = |\vec w| and if the area of the parallelogram PQRSPQRS is 8, then which of the following statements is/are TRUE?

Choose one or more options
Answer and worked solution

Official answer: A, C

Projections.
∣u⃗∣=a+ba2+b2,∣v⃗∣=∣a−b∣a2+b2.|\vec u|=\frac{a+b}{\sqrt{a^2+b^2}},\qquad|\vec v|=\frac{|a-b|}{\sqrt{a^2+b^2}}.

The condition ∣u⃗∣+∣v⃗∣=2|\vec u|+|\vec v|=\sqrt2:
2max⁡(a,b)a2+b2=2  ⟹  2max⁡(a,b)2=a2+b2  ⟹  a=b.\frac{2\max(a,b)}{\sqrt{a^2+b^2}}=\sqrt2\implies2\max(a,b)^2=a^2+b^2\implies a=b.

Area. ∣PQ→×PS→∣=2ab=8|\overrightarrow{PQ}\times\overrightarrow{PS}|=2ab=8, so a=b=2a=b=2.

The statements.

  • (A) a+b=4a+b=4. True.
  • (B) a−b=0≠2a-b=0\ne2. False.
  • (C) PR→=PQ→+PS→=(4,0)\overrightarrow{PR}=\overrightarrow{PQ}+\overrightarrow{PS}=(4,0), of length 4. True.
  • (D) The bisector of (2,2)(2,2) and (2,−2)(2,-2) is along i^\hat i, while w⃗=i^+j^\vec w=\hat i+\hat j is along PQ→\overrightarrow{PQ} itself. False.

(A), (C)