JEE Advanced 2019 · Paper 1 · Chemistry Q13

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ChemistryNumerical+3Question 31 of 54

Among $\ce{B2H6}$ , $\ce{B3N3H6}$ , $\ce{N2O}$ , $\ce{N2O4}$ , $\ce{H2S2O3}$ and $\ce{H2S2O8}$ , the total number of molecules containing covalent bond between two atoms of the same kind is ______

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Answer and worked solution

Official answer: 4

$\ce{B2H6}$ : B-H-B bridges, no B-B bond. ✗
$\ce{B3N3H6}$ : alternating B-N ring. ✗
$\ce{N2O}$ ( $\ce{N=N=O}$ ): N-N bond. ✓
$\ce{N2O4}$ ( $\ce{O2N-NO2}$ ): N-N bond. ✓
$\ce{H2S2O3}$ : S=S (S-S) bond. ✓
$\ce{H2S2O8}$ : O-O peroxide bridge. ✓

Answer: 4

Topics:Covalent bonding and Lewis structures

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JEE Advanced 2019 · Paper 1, Chemistry question 13