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← JEE Advanced 2018 · Paper 2
PhysicsList match+3 / -1Question 15 of 54

JEE Advanced 2018 · Paper 2, Physics question 15

The electric field EE is measured at a point P(0,0,d)P(0, 0, d) generated due to various charge distributions and the dependence of EE on dd is found to be different for different charge distributions. List-I contains different relations between EE and dd. List-II describes different electric charge distributions, along with their locations. Match the functions in List-I with the related charge distributions in List-II.

LIST-I

  • P
    EE is independent of dd
  • Q
    E∝1dE \propto \dfrac{1}{d}
  • R
    E∝1d2E \propto \dfrac{1}{d^2}
  • S
    E∝1d3E \propto \dfrac{1}{d^3}

LIST-II

  • 1
    A point charge QQ at the origin
  • 2
    A small dipole with point charges QQ at (0,0,l)(0, 0, l) and −Q-Q at (0,0,−l)(0, 0, -l). Take 2l≪d2l \ll d
  • 3
    An infinite line charge coincident with the xx-axis, with uniform linear charge density λ\lambda
  • 4
    Two infinite wires carrying uniform linear charge density parallel to the xx-axis. The one along (y=0,z=l)(y = 0, z = l) has a charge density +λ+\lambda and the one along (y=0,z=−l)(y = 0, z = -l) has a charge density −λ-\lambda. Take 2l≪d2l \ll d
  • 5
    Infinite plane charge coincident with the xyxy-plane with uniform surface charge density
Choose one option
Answer and worked solution

Official answer: B

Field at (0,0,d)(0,0,d) for each distribution:

  1. Point charge: E=kQd2∝1d2E=\dfrac{kQ}{d^2}\propto\dfrac1{d^2}.
  2. Small dipole along zz, on its axis: E=2k(2lQ)d3∝1d3E=\dfrac{2k(2lQ)}{d^3}\propto\dfrac1{d^3}.
  3. Infinite line along xx, a distance dd away: E=λ2πϵ0d∝1dE=\dfrac\lambda{2\pi\epsilon_0d}\propto\dfrac1d.
  4. Two opposite lines a distance 2l2l apart (a line dipole): the 1/d1/d terms cancel, leaving E≈λ(2l)2πϵ0d2∝1d2E\approx\dfrac{\lambda(2l)}{2\pi\epsilon_0d^2}\propto\dfrac1{d^2}.
  5. Infinite plane: E=σ2ϵ0E=\dfrac\sigma{2\epsilon_0}, independent of dd.

Match. P → 5; Q → 3; R → 1, 4; S → 2.

(B)