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← JEE Advanced 2018 · Paper 1
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JEE Advanced 2018 · Paper 1, Mathematics question 7

The value of

((log⁡29)2)1log⁡2(log⁡29)×(7)1log⁡47\left((\log_2 9)^2\right)^{\frac{1}{\log_2(\log_2 9)}} \times (\sqrt{7})^{\frac{1}{\log_4 7}}

is ______ .

Answer and worked solution

Official answer: 8

First factor. Use a1/log⁡2a=2a^{1/\log_2a}=2 with a=log⁡29a=\log_29:
((log⁡29)2)1log⁡2(log⁡29)=(a1/log⁡2a)2=22=4.\left((\log_29)^2\right)^{\frac1{\log_2(\log_29)}}=\left(a^{1/\log_2a}\right)^2=2^2=4.

Second factor.
(7)1log⁡47=712log⁡74=41/2=2.(\sqrt7)^{\frac1{\log_47}}=7^{\frac12\log_74}=4^{1/2}=2.

Product: 4×2=84\times2=8.

Answer: 8

Topics:Logarithms