Skip to content
dronacharya.ai
← JEE Advanced 2018 · Paper 1
ChemistrySingle correct+3 / -1Question 34 of 54

JEE Advanced 2018 · Paper 1, Chemistry question 16

Passage

Treatment of benzene with CO/HCl in the presence of anhydrous AlCl3_3/CuCl followed by reaction with Ac2_2O/NaOAc gives compound X as the major product. Compound X upon reaction with Br2_2/Na2_2CO3_3, followed by heating at 473 K with moist KOH furnishes Y as the major product. Reaction of X with H2_2/Pd-C, followed by H3_3PO4_4 treatment gives Z as the major product.

The compound Z is

Choose one option
Answer and worked solution

Official answer: A

  • HX2/Pd−C\ce{H2/Pd-C} reduces the C=C of cinnamic acid, giving 3-phenylpropanoic acid, PhCHX2CHX2COOH\ce{PhCH2CH2COOH}.
  • Hot phosphoric acid causes an intramolecular Friedel-Crafts acylation onto the ring. This closes a five-membered ring, giving 1-indanone. This is Z.

(A)