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← JEE Advanced 2018 · Paper 1
ChemistryNumerical+3Question 25 of 54

JEE Advanced 2018 · Paper 1, Chemistry question 7

Among the species given below, the total number of diamagnetic species is ______.

H atom, NOX2\ce{NO2} monomer, OX2X−\ce{O2-} (superoxide), dimeric sulphur in vapour phase, MnX3OX4\ce{Mn3O4}, (NHX4)X2[FeClX4]\ce{(NH4)2[FeCl4]}, (NHX4)X2[NiClX4]\ce{(NH4)2[NiCl4]}, KX2MnOX4\ce{K2MnO4}, KX2CrOX4\ce{K2CrO4}

Answer and worked solution

Official answer: 1

Count unpaired electrons:

Species Unpaired electrons
H atom 1
NOX2\ce{NO2} (odd-electron) 1
OX2X−\ce{O2-} 1
SX2\ce{S2} (vapour, like OX2\ce{O2}) 2
MnX3OX4\ce{Mn3O4} (MnX2+\ce{Mn^{2+}}, MnX3+\ce{Mn^{3+}}) many
[FeClX4]X2−\ce{[FeCl4]^{2-}} (Fe²⁺, d⁶, high spin) 4
[NiClX4]X2−\ce{[NiCl4]^{2-}} (Ni²⁺, d⁸, tetrahedral) 2
KX2MnOX4\ce{K2MnO4} (Mn(VI), d¹) 1
KX2CrOX4\ce{K2CrO4} (Cr(VI), d⁰) 0

Only KX2CrOX4\ce{K2CrO4} is diamagnetic.

Answer: 1