JEE Advanced 2017 · Paper 2, Chemistry question 18

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The reaction of compound P with $\ce{CH3MgBr}$ (excess) in $\ce{(C2H5)2O}$ followed by addition of $\ce{H2O}$ gives Q. The compound Q on treatment with $\ce{H2SO4}$ at 0°C gives R. The reaction of R with $\ce{CH3COCl}$ in the presence of anhydrous $\ce{AlCl3}$ in $\ce{CH2Cl2}$ followed by treatment with $\ce{H2O}$ produces compound S. [Et in compound P is ethyl group]

P → Q → R → S