JEE Advanced 2017 · Paper 2 · Chemistry Q5

ChemistrySingle correct+3 / -1Question 23 of 54

The order of the oxidation state of the phosphorus atom in $\ce{H3PO2}$ , $\ce{H3PO4}$ , $\ce{H3PO3}$ , and $\ce{H4P2O6}$ is

\ce{H3PO3} > \ce{H3PO2} > \ce{H3PO4} > \ce{H4P2O6}

\ce{H3PO4} > \ce{H3PO2} > \ce{H3PO3} > \ce{H4P2O6}

\ce{H3PO4} > \ce{H4P2O6} > \ce{H3PO3} > \ce{H3PO2}

\ce{H3PO2} > \ce{H3PO3} > \ce{H4P2O6} > \ce{H3PO4}

Answer and worked solution

Official answer: C

Oxidation states of P:

So $\ce{H3PO4 > H4P2O6 > H3PO3 > H3PO2}$ .

(C)

Topics:Oxidation number Oxoacids

JEE Advanced 2017 · Paper 2, Chemistry question 5