Skip to content
dronacharya.ai
← JEE Advanced 2017 · Paper 1
PhysicsInteger+3Question 12 of 54

JEE Advanced 2017 · Paper 1, Physics question 12

131{}^{131}I is an isotope of Iodine that β\beta decays to an isotope of Xenon with a half-life of 8 days. A small amount of a serum labelled with 131{}^{131}I is injected into the blood of a person. The activity of the amount of 131{}^{131}I injected was 2.4×1052.4 \times 10^5 Becquerel (Bq). It is known that the injected serum will get distributed uniformly in the blood stream in less than half an hour. After 11.5 hours, 2.5 ml of blood is drawn from the person’s body, and gives an activity of 115 Bq. The total volume of blood in the person’s body, in liters is approximately (you may use ex≈1+xe^x \approx 1 + x for ∣x∣≪1|x| \ll 1 and ln⁡2≈0.7\ln 2 \approx 0.7).

Answer and worked solution

Official answer: 5

Decay. λ=0.78 day−1\lambda=\dfrac{0.7}8\ \text{day}^{-1} and t=11.5 h=11.524t=11.5\text{ h}=\dfrac{11.5}{24} day, so
λt=0.7×11.58×24≈0.042.\lambda t=\frac{0.7\times11.5}{8\times24}\approx0.042.
The total activity now is
A≈2.4×105(1−0.042)≈2.30×105 Bq.A\approx2.4\times10^5(1-0.042)\approx2.30\times10^5\text{ Bq}.

Dilution. The sample shows 1152.5=46\dfrac{115}{2.5}=46 Bq per ml, so
V=2.30×10546≈5000 ml=5 L.V=\frac{2.30\times10^5}{46}\approx5000\text{ ml}=5\text{ L}.

Answer: 5