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← JEE Advanced 2016 · Paper 2
MathematicsSingle correct+3Question 52 of 54

JEE Advanced 2016 · Paper 2, Mathematics question 52

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PARAGRAPH 1

Football teams T1T_1 and T2T_2 have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of T1T_1 winning, drawing and losing a game against T2T_2 are 12\frac12, 16\frac16 and 13\frac13, respectively. Each team gets 3 points for a win, 1 point for a draw and 0 point for a loss in a game. Let XX and YY denote the total points scored by teams T1T_1 and T2T_2, respectively, after two games.

P(X=Y)P(X=Y) is

Choose one option
Answer and worked solution

Official answer: C

X=YX=Y happens for:

  • two draws: 136\frac1{36};
  • one win and one loss: 2⋅12⋅13=132\cdot\frac12\cdot\frac13=\frac13.

P(X=Y)=136+1236=1336.P(X=Y)=\frac1{36}+\frac{12}{36}=\frac{13}{36}.

(C)