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← JEE Advanced 2016 · Paper 2
MathematicsMultiple correct+4 / -2Question 43 of 54

JEE Advanced 2016 · Paper 2, Mathematics question 43

Let f(x)=lim⁡n→∞(nn(x+n)(x+n2)⋯(x+nn)n! (x2+n2)(x2+n24)⋯(x2+n2n2))x/nf(x)=\displaystyle\lim_{n\to\infty}\left(\frac{n^n(x+n)\left(x+\frac n2\right)\cdots\left(x+\frac nn\right)}{n!\,(x^2+n^2)\left(x^2+\frac{n^2}{4}\right)\cdots\left(x^2+\frac{n^2}{n^2}\right)}\right)^{x/n}, for all x>0x>0. Then

Choose one or more options
Answer and worked solution

Official answer: B, C

Take logs. For each rr, the factor is nr⋅x+n/rx2+n2/r2=1+x(r/n)1+x2(r/n)2\dfrac{n}{r}\cdot\dfrac{x+n/r}{x^2+n^2/r^2}=\dfrac{1+x(r/n)}{1+x^2(r/n)^2}. As a Riemann sum,
ln⁡f(x)=x∫01ln⁡1+xt1+x2t2 dt=∫0xln⁡1+u1+u2 du.\ln f(x)=x\int_0^1\ln\frac{1+xt}{1+x^2t^2}\,dt=\int_0^x\ln\frac{1+u}{1+u^2}\,du.

Derivative.
f′(x)f(x)=ln⁡1+x1+x2.\frac{f'(x)}{f(x)}=\ln\frac{1+x}{1+x^2}.
This is positive for x<1x<1 and negative for x>1x>1.

  • (A) ff increases on (0,1)(0,1), so f(12)<f(1)f(\frac12)<f(1). False.
  • (B) f(13)<f(23)f(\frac13)<f(\frac23). True.
  • (C) f′(2)f'(2) has the sign of ln⁡35<0\ln\frac35<0. True.
  • (D) ln⁡410<ln⁡35\ln\frac4{10}<\ln\frac35. False.

(B), (C)