JEE Advanced 2016 · Paper 2 · Chemistry Q29

ChemistryMultiple correct+4 / -2Question 29 of 54

The nitrogen containing compound produced in the reaction of $\ce{HNO3}$ with $\ce{P4O10}$

can also be prepared by reaction of

\ce{P4}

and

\ce{HNO3}

is diamagnetic

contains one N-N bond

reacts with Na metal producing a brown gas

Answer and worked solution

Official answer: B, D

The product. $\ce{P4O10}$ dehydrates nitric acid:
$\ce{4HNO3 + P4O10 -> 2N2O5 + 4HPO3}.$
So the nitrogen compound is $\ce{N2O5}$ .

(A) $\ce{P4}$ with $\ce{HNO3}$ gives $\ce{H3PO4}$ and $\ce{NO2}$ , not $\ce{N2O5}$ . False.
(B) All its electrons are paired: diamagnetic. True.
(C) $\ce{O2N-O-NO2}$ has an N-O-N bridge, no N-N bond. False.
(D) $\ce{Na + N2O5 -> NaNO3 + NO2}$ releases brown NO₂. True.

(B), (D)

Topics:Group 15 Oxoacids

JEE Advanced 2016 · Paper 2, Chemistry question 29