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← JEE Advanced 2016 · Paper 1
PhysicsMultiple correct+4 / -2Question 12 of 54

JEE Advanced 2016 · Paper 1, Physics question 12

The position vector r⃗\vec r of a particle of mass mm is given by the following equation
r⃗(t)=αt3 i^+βt2 j^,\vec r(t)=\alpha t^3\,\hat i+\beta t^2\,\hat j,
where α=10/3 m s−3\alpha=10/3\ \mathrm{m\,s^{-3}}, β=5 m s−2\beta=5\ \mathrm{m\,s^{-2}} and m=0.1m=0.1 kg. At t=1t=1 s, which of the following statement(s) is(are) true about the particle?

Choose one or more options
Answer and worked solution

Official answer: A, B, D

Kinematics.
v⃗=3αt2i^+2βtj^=(10i^+10j^) m s−1 at t=1.\vec v=3\alpha t^2\hat i+2\beta t\hat j=(10\hat i+10\hat j)\text{ m s}^{-1}\text{ at }t=1.
a⃗=6αti^+2βj^=(20i^+10j^) m s−2.\vec a=6\alpha t\hat i+2\beta\hat j=(20\hat i+10\hat j)\text{ m s}^{-2}.
The position at t=1t=1 is r⃗=103i^+5j^\vec r=\frac{10}3\hat i+5\hat j.

  • (A) True.
  • (B) L⃗=m r⃗×v⃗=0.1(103⋅10−5⋅10)k^=−53k^\vec L=m\,\vec r\times\vec v=0.1\left(\frac{10}3\cdot10-5\cdot10\right)\hat k=-\frac53\hat k N m s. True.
  • (C) F⃗=ma⃗=(2i^+j^)\vec F=m\vec a=(2\hat i+\hat j) N. False.
  • (D) τ⃗=r⃗×F⃗=(103⋅1−5⋅2)k^=−203k^\vec\tau=\vec r\times\vec F=\left(\frac{10}3\cdot1-5\cdot2\right)\hat k=-\frac{20}3\hat k N m. True.

(A), (B), (D)