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← JEE Advanced 2015 · Paper 2
PhysicsInteger+4Question 5 of 60

JEE Advanced 2015 · Paper 2, Physics question 5

For a radioactive material, its activity AA and rate of change of its activity RR are defined as A=−dNdtA=-\dfrac{dN}{dt} and R=−dAdtR=-\dfrac{dA}{dt}, where N(t)N(t) is the number of nuclei at time tt. Two radioactive sources PP (mean life τ\tau) and QQ (mean life 2τ2\tau) have the same activity at t=0t=0. Their rates of change of activities at t=2τt=2\tau are RPR_P and RQR_Q, respectively. If RPRQ=ne\dfrac{R_P}{R_Q}=\dfrac ne, then the value of nn is

Answer and worked solution

Official answer: 2

Rate of change of activity. A=A0e−λtA=A_0e^{-\lambda t}, so R=λA0e−λtR=\lambda A_0e^{-\lambda t}.

At t = 2τ.

  • RP=1τA0e−2R_P=\dfrac1\tau A_0e^{-2}.
  • RQ=12τA0e−1R_Q=\dfrac1{2\tau}A_0e^{-1}.

Ratio. RPRQ=2e\dfrac{R_P}{R_Q}=\dfrac2e, so n=2n=2.

Answer: 2