JEE Advanced 2015 · Paper 2, Chemistry question 38
Passage
PARAGRAPH 1
In the following reactions CX8HX6Pd-BaSO4HX2CX8HX8i. BX2HX6ii. HX2OX2,NaOH,HX2OX CX8HX6HX2O,HgSOX4,HX2SOX4CX8HX8Oi. EtMgBr, HX2Oii. HX+, heatY
The major compound Y is
Answer and worked solution
Official answer: D
HgSO₄/H₂SO₄ hydration of phenylacetylene gives acetophenone (C₈H₈O).
EtMgBr gives PhC(OH)(CHX3)CHX2CHX3.
H⁺, heat dehydrates it to the most substituted, conjugated alkene: PhC(CHX3)=CHCHX3.