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← JEE Advanced 2015 · Paper 2
ChemistryMultiple correct+4 / -2Question 38 of 60

JEE Advanced 2015 · Paper 2, Chemistry question 38

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PARAGRAPH 1

In the following reactions
CX8HX6→HX2Pd-BaSO4CX8HX8→ii. HX2OX2, NaOH, HX2Oi. BX2HX6X\ce{C8H6}\xrightarrow[\ce{H2}]{\text{Pd-BaSO}_4}\ce{C8H8}\xrightarrow[\text{ii. }\ce{H2O2},\ \ce{NaOH},\ \ce{H2O}]{\text{i. }\ce{B2H6}}\mathbf X
CX8HX6→HX2O, HgSOX4, HX2SOX4CX8HX8O→ii. HX+, heati. EtMgBr, HX2OY\ce{C8H6}\xrightarrow{\ce{H2O},\ \ce{HgSO4},\ \ce{H2SO4}}\ce{C8H8O}\xrightarrow[\text{ii. }\ce{H+},\text{ heat}]{\text{i. EtMgBr, }\ce{H2O}}\mathbf Y

The major compound Y is

Choose one or more options
Answer and worked solution

Official answer: D

  1. HgSO₄/H₂SO₄ hydration of phenylacetylene gives acetophenone (C₈H₈O).
  2. EtMgBr gives PhC(OH)(CHX3)CHX2CHX3\ce{PhC(OH)(CH3)CH2CH3}.
  3. H⁺, heat dehydrates it to the most substituted, conjugated alkene: PhC(CHX3)=CHCHX3\ce{PhC(CH3)=CHCH3}.

(D)