JEE Advanced 2015 · Paper 2 · Chemistry Q36

← JEE Advanced 2015 · Paper 2

ChemistryMultiple correct+4 / -2Question 36 of 60

One mole of a monoatomic real gas satisfies the equation $p(V-b)=RT$ where $b$ is a constant. The relationship of interatomic potential $V(r)$ and interatomic distance $r$ for the gas is given by

V(r) against r: very large at small r, dropping into an attractive well below zero and rising back towards zero (Lennard-Jones shape).

V(r) against r: infinite (vertical wall) below a finite r, then zero for larger r (hard sphere).

V(r) against r: an infinite wall at small r, then a square attractive well below zero, then zero.

Answer and worked solution

Official answer: C

In $p(V-b)=RT$ there is no attraction term ( $a=0$ ), only an excluded volume $b$ . That is a hard-sphere potential: infinite below the contact distance and zero beyond it.

(C)

Topics:Real gases and van der Waals equation

← Previous question Next question →

JEE Advanced 2015 · Paper 2, Chemistry question 36