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← JEE Advanced 2015 · Paper 1
ChemistryMultiple correct+4 / -2Question 33 of 60

JEE Advanced 2015 · Paper 1, Chemistry question 33

The major product of the reaction is

Leucine, (CH₃)₂CH-CH₂-CH(NH₂)-CO₂H, with the NH₂ on a wedge at C2, treated with NaNO₂, aqueous HCl at 0 °C.
Choose one or more options
Answer and worked solution

Official answer: C

Diazotisation. NaNO₂/HCl diazotises the α-amino group.

Neighbouring-group participation. The carboxylate displaces N₂ with inversion, forming an α-lactone. Water then opens it with a second inversion.

Result. Two inversions mean overall retention: 2-hydroxy-4-methylpentanoic acid with the OH in the same position as the original NH₂ (wedge).

(C)