JEE Advanced 2015 · Paper 1 · Chemistry Q28

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ChemistryInteger+4Question 28 of 60

If the freezing point of a 0.01 molal aqueous solution of a cobalt(III) chloride-ammonia complex (which behaves as a strong electrolyte) is −0.0558 °C, the number of chloride(s) in the coordination sphere of the complex is

[ $K_f$ of water = 1.86 K kg mol⁻¹]

Your answer

Answer and worked solution

Official answer: 1

Van 't Hoff factor.
$0.0558=i(1.86)(0.01)\implies i=3.$

Formula. Three ions means $\ce{[Co(NH3)5Cl]Cl2}$ : one chloride in the coordination sphere.

Answer: 1

Topics:van't Hoff factor Colligative properties Nomenclature

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JEE Advanced 2015 · Paper 1, Chemistry question 28