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← JEE Advanced 2014 · Paper 2
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JEE Advanced 2014 · Paper 2, Physics question 4

Charges QQ, 2Q2Q and 4Q4Q are uniformly distributed in three dielectric solid spheres 1, 2 and 3 of radii R/2R/2, RR and 2R2R, respectively, as shown in figure. If magnitudes of the electric fields at point PP at a distance RR from the center of spheres 1, 2 and 3 are E1E_1, E2E_2 and E3E_3 respectively, then

Three uniformly charged dielectric spheres: sphere 1 (radius R/2, charge Q) with P outside at distance R from its centre; sphere 2 (radius R, charge 2Q) with P on its surface; sphere 3 (radius 2R, charge 4Q) with P inside at distance R from its centre.
Choose one option
Answer and worked solution

Official answer: C

Let k=14πε0k=\frac1{4\pi\varepsilon_0}.

  • Sphere 1 (P outside): E1=kQR2E_1=\dfrac{kQ}{R^2}.
  • Sphere 2 (P on the surface): E2=k(2Q)R2E_2=\dfrac{k(2Q)}{R^2}.
  • Sphere 3 (P inside, uniform charge): E3=k(4Q)R(2R)3=kQ2R2E_3=\dfrac{k(4Q)R}{(2R)^3}=\dfrac{kQ}{2R^2}.

So E2>E1>E3E_2>E_1>E_3.

(C)