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← JEE Advanced 2014 · Paper 2
MathematicsSingle correct+3 / -1Question 43 of 60

JEE Advanced 2014 · Paper 2, Mathematics question 43

Coefficient of x11x^{11} in the expansion of (1+x2)4(1+x3)7(1+x4)12(1+x^2)^4(1+x^3)^7(1+x^4)^{12} is

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Answer and worked solution

Official answer: C

Exponents. Choose x2ix^{2i}, x3jx^{3j}, x4kx^{4k} with 2i+3j+4k=112i+3j+4k=11, 0≤i≤40\le i\le4, 0≤j≤70\le j\le7, 0≤k≤120\le k\le12. 3j3j must be odd, so j∈{1,3}j\in\{1,3\}.

(i,j,k)(i,j,k) term
(0,1,2)(0,1,2) (71)(122)=7×66=462\binom71\binom{12}2=7\times66=462
(2,1,1)(2,1,1) (42)(71)(121)=6×7×12=504\binom42\binom71\binom{12}1=6\times7\times12=504
(4,1,0)(4,1,0) (44)(71)=7\binom44\binom71=7
(1,3,0)(1,3,0) (41)(73)=4×35=140\binom41\binom73=4\times35=140

Sum. 462+504+7+140=1113462+504+7+140=1113.

(C)