Exponents. Choose x2i, x3j, x4k with 2i+3j+4k=11, 0≤i≤4, 0≤j≤7, 0≤k≤12. 3j must be odd, so j∈{1,3}.
| (i,j,k) |
term |
| (0,1,2) |
(17)(212)=7×66=462 |
| (2,1,1) |
(24)(17)(112)=6×7×12=504 |
| (4,1,0) |
(44)(17)=7 |
| (1,3,0) |
(14)(37)=4×35=140 |
Sum. 462+504+7+140=1113.
(C)