JEE Advanced 2014 · Paper 2 · Chemistry Q28

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ChemistrySingle correct+3 / -1Question 28 of 60

For the elementary reaction $\ce{M -> N}$ , the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is

Answer and worked solution

Official answer: B

Rate law. For an elementary step the order equals the molecularity, rate $=k[\ce M]^n$ . Doubling $[\ce M]$ multiplies the rate by $2^n=8$ , so $n=3$ .

(B)

Topics:Order and molecularity Rate of reaction and rate law

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JEE Advanced 2014 · Paper 2, Chemistry question 28