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← JEE Advanced 2014 · Paper 1
PhysicsInteger+3Question 15 of 60

JEE Advanced 2014 · Paper 1, Physics question 15

To find the distance dd over which a signal can be seen clearly in foggy conditions, a railways engineer uses dimensional analysis and assumes that the distance depends on the mass density ρ\rho of the fog, intensity (power/area) SS of the light from the signal and its frequency ff. The engineer finds that dd is proportional to S1/nS^{1/n}. The value of nn is

Answer and worked solution

Official answer: 3

Dimensions. Write d=kρaSbfcd=k\rho^aS^bf^c with [ρ]=ML−3[\rho]=\mathrm{ML^{-3}}, [S]=MT−3[S]=\mathrm{MT^{-3}} (power per area) and [f]=T−1[f]=\mathrm T^{-1}.

L1=Ma+b L−3a T−3b−c.\mathrm L^1=\mathrm M^{a+b}\,\mathrm L^{-3a}\,\mathrm T^{-3b-c}.

  • L: −3a=1-3a=1, so a=−13a=-\frac13.
  • M: a+b=0a+b=0, so b=13b=\frac13.
  • T: c=−3b=−1c=-3b=-1.

So d∝S1/3d\propto S^{1/3} and n=3n=3.

Answer: 3