Skip to content
dronacharya.ai
← JEE Advanced 2014 · Paper 1
ChemistryInteger+3Question 38 of 60

JEE Advanced 2014 · Paper 1, Chemistry question 38

If the value of Avogadro number is 6.023×1023 mol−16.023\times10^{23}\ \mathrm{mol^{-1}} and the value of Boltzmann constant is 1.380×10−23 J K−11.380\times10^{-23}\ \mathrm{J\,K^{-1}}, then the number of significant digits in the calculated value of the universal gas constant is

Answer and worked solution

Official answer: 4

Calculation. R=NAkB=6.023×1023×1.380×10−23=8.31174 J K−1 mol−1R=N_Ak_B=6.023\times10^{23}\times1.380\times10^{-23}=8.31174\ \mathrm{J\,K^{-1}\,mol^{-1}}.

Significant figures. Both factors have 4 significant figures, so the product is reported to 4: R=8.312 J K−1 mol−1R=8.312\ \mathrm{J\,K^{-1}\,mol^{-1}}.

Answer: 4

Topics:Mole concept
← Previous questionNext question →