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← JEE Advanced 2013 · Paper 2
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JEE Advanced 2013 · Paper 2, Physics question 18

A right angled prism of refractive index μ1\mu_1 is placed in a rectangular block of refractive index μ2\mu_2, which is surrounded by a medium of refractive index μ3\mu_3, as shown in the figure. A ray of light 'ee' enters the rectangular block at normal incidence. Depending upon the relationships between μ1\mu_1, μ2\mu_2 and μ3\mu_3, it takes one of the four possible paths 'efef', 'egeg', 'eheh' or 'eiei'.

Match the paths in List I with conditions of refractive indices in List II and select the correct answer using the codes given below the lists:

A rectangular block (index μ₂) in a medium μ₃ contains a right-angled isosceles prism (index μ₁) with its vertical face on the left and hypotenuse faces at 45°. Ray e enters horizontally from the left, crosses the vertical face and meets the upper slanted face at 45°: it can leave bent upward (f), straight (g), bent downward (h), or be totally reflected down to the lower slanted face and back out to the left as ray i.

List I

  • P
    e→fe\to f
  • Q
    e→ge\to g
  • R
    e→he\to h
  • S
    e→ie\to i

List II

  • 1
    μ1>2 μ2\mu_1>\sqrt2\,\mu_2
  • 2
    μ2>μ1\mu_2>\mu_1 and μ2>μ3\mu_2>\mu_3
  • 3
    μ1=μ2\mu_1=\mu_2
  • 4
    μ2<μ1<2 μ2\mu_2<\mu_1<\sqrt2\,\mu_2 and μ2>μ3\mu_2>\mu_3
Choose one option
Answer and worked solution

Official answer: D

At the slanted face the ray inside the prism (index μ1\mu_1) meets the boundary with μ2\mu_2 at 45°.

  • e→fe\to f (bends away from the normal toward the upper side): passes into a denser block, μ2>μ1\mu_2>\mu_1, and then leaves into μ3\mu_3 with μ2>μ3\mu_2>\mu_3. → 2
  • e→ge\to g (undeviated): μ1=μ2\mu_1=\mu_2. → 3
  • e→he\to h (bends the other way, no total reflection): μ2<μ1<2μ2\mu_2<\mu_1<\sqrt2\mu_2 (so sin⁡45°<μ2/μ1\sin45°<\mu_2/\mu_1), with μ2>μ3\mu_2>\mu_3. → 4
  • e→ie\to i (totally reflected twice and sent back): sin⁡45°>μ2μ1\sin45°>\frac{\mu_2}{\mu_1}, i.e. μ1>2μ2\mu_1>\sqrt2\mu_2. → 1

Code 2 3 4 1.

(D)