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← JEE Advanced 2013 · Paper 2
MathematicsList match+3 / -1Question 60 of 60

JEE Advanced 2013 · Paper 2, Mathematics question 60

Match List I with List II and select the correct answer using the code given below the lists:

List I

  • P
    Volume of parallelepiped determined by vectors a⃗\vec a, b⃗\vec b and c⃗\vec c is 2. Then the volume of the parallelepiped determined by vectors 2(a⃗×b⃗)2(\vec a\times\vec b), 3(b⃗×c⃗)3(\vec b\times\vec c) and (c⃗×a⃗)(\vec c\times\vec a) is
  • Q
    Volume of parallelepiped determined by vectors a⃗\vec a, b⃗\vec b and c⃗\vec c is 5. Then the volume of the parallelepiped determined by vectors 3(a⃗+b⃗)3(\vec a+\vec b), (b⃗+c⃗)(\vec b+\vec c) and 2(c⃗+a⃗)2(\vec c+\vec a) is
  • R
    Area of a triangle with adjacent sides determined by vectors a⃗\vec a and b⃗\vec b is 20. Then the area of the triangle with adjacent sides determined by vectors (2a⃗+3b⃗)(2\vec a+3\vec b) and (a⃗−b⃗)(\vec a-\vec b) is
  • S
    Area of a parallelogram with adjacent sides determined by vectors a⃗\vec a and b⃗\vec b is 30. Then the area of the parallelogram with adjacent sides determined by vectors (a⃗+b⃗)(\vec a+\vec b) and a⃗\vec a is

List II

  • 1
    100
  • 2
    30
  • 3
    24
  • 4
    60
Choose one option
Answer and worked solution

Official answer: C

  • P: [a⃗×b⃗, b⃗×c⃗, c⃗×a⃗]=[a⃗ b⃗ c⃗]2=4[\vec a\times\vec b,\ \vec b\times\vec c,\ \vec c\times\vec a]=[\vec a\,\vec b\,\vec c]^2=4; with the factors 2⋅32\cdot3: 24. → 3
  • Q: [a⃗+b⃗, b⃗+c⃗, c⃗+a⃗]=2[a⃗ b⃗ c⃗]=10[\vec a+\vec b,\ \vec b+\vec c,\ \vec c+\vec a]=2[\vec a\,\vec b\,\vec c]=10; with 3⋅23\cdot2: 60. → 4
  • R: (2a⃗+3b⃗)×(a⃗−b⃗)=−5 a⃗×b⃗(2\vec a+3\vec b)\times(\vec a-\vec b)=-5\,\vec a\times\vec b: area 5×20=1005\times20=100. → 1
  • S: (a⃗+b⃗)×a⃗=b⃗×a⃗(\vec a+\vec b)\times\vec a=\vec b\times\vec a: area 30. → 2

Code 3 4 1 2.

(C)