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← JEE Advanced 2013 · Paper 2
MathematicsMultiple correct+3 / -1Question 48 of 60

JEE Advanced 2013 · Paper 2, Mathematics question 48

In a triangle PQRPQR, PP is the largest angle and cos⁡P=13\cos P=\frac13. Further the incircle of the triangle touches the sides PQPQ, QRQR and RPRP at NN, LL and MM respectively, such that the lengths of PNPN, QLQL and RMRM are consecutive even integers. Then possible length(s) of the side(s) of the triangle is (are)

Choose one or more options
Answer and worked solution

Official answer: B, D

Tangent lengths. With PN=xPN=x, QL=yQL=y, RM=zRM=z: QR=y+zQR=y+z, RP=z+xRP=z+x, PQ=x+yPQ=x+y. PP is the largest angle, so QRQR is the largest side and xx is the smallest tangent length: x=2kx=2k, {y,z}={2k+2,2k+4}\{y,z\}=\{2k+2,2k+4\}.

Sides. With m=2k+2m=2k+2: QR=2(m+1)QR=2(m+1) and the others 2(m−1)2(m-1), 2m2m.

Cosine rule.
cos⁡P=(m−1)2+m2−(m+1)22m(m−1)=m−42(m−1)=13  ⟹  m=10.\cos P=\frac{(m-1)^2+m^2-(m+1)^2}{2m(m-1)}=\frac{m-4}{2(m-1)}=\frac13\implies m=10.

Sides 18, 20, 22.

(B), (D)