JEE Advanced 2013 · Paper 2 · Chemistry Q38

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ChemistryList match+3 / -1Question 38 of 60

The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists:

List I

P
$\ce{PbO2 + H2SO4 ->[?] PbSO4 + O2}$ + other product
Q
$\ce{Na2S2O3 + H2O ->[?] NaHSO4}$ + other product
R
$\ce{N2H4 ->[?] N2}$ + other product
S
$\ce{XeF2 ->[?] Xe}$ + other product

List II

1
NO
2
$\ce{I2}$
3
Warm
4
$\ce{Cl2}$

P → 4; Q → 2; R → 3; S → 1

P → 3; Q → 2; R → 1; S → 4

P → 1; Q → 4; R → 2; S → 3

P → 3; Q → 4; R → 2; S → 1

Answer and worked solution

Official answer: D

P: $\ce{2PbO2 + 2H2SO4 ->[warm] 2PbSO4 + O2 + 2H2O}$ . → 3
Q: $\ce{Na2S2O3 + 4Cl2 + 5H2O -> 2NaHSO4 + 8HCl}$ . → 4
R: $\ce{N2H4 + 2I2 -> N2 + 4HI}$ . → 2
S: $\ce{XeF2 + 2NO -> Xe + 2NOF}$ . → 1

Code 3 4 2 1.

(D)

Topics:Balancing redox reactions Group 18 Group 16

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JEE Advanced 2013 · Paper 2, Chemistry question 38