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ChemistrySingle correct+3 / -1Question 29 of 60

JEE Advanced 2013 · Paper 2, Chemistry question 29

Passage

Paragraph for Questions 29 and 30

A fixed mass 'mm' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure

Pressure against volume: a rectangle with K at top-left, L at top-right, M at bottom-right and N at bottom-left; the cycle runs K → L (isobaric expansion) → M (isochoric drop) → N (isobaric compression) → K (isochoric rise).

The succeeding operations that enable this transformation of states are

Choose one option
Answer and worked solution

Official answer: C

From PV = nRT (fixed mass):

  • K → L: P constant, V up: T rises (heating).
  • L → M: V constant, P down: T falls (cooling).
  • M → N: P constant, V down: T falls (cooling).
  • N → K: V constant, P up: T rises (heating).

(C)

Topics:Gas laws
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