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← JEE Advanced 2013 · Paper 2
ChemistryMultiple correct+3 / -1Question 22 of 60

JEE Advanced 2013 · Paper 2, Chemistry question 22

In the nuclear transmutation
X49X2429Be+X→X48X2428Be+Y\ce{^9_4Be + X -> ^8_4Be + Y}
(X, Y) is(are)

Choose one or more options
Answer and worked solution

Official answer: A, B

Balance A and Z. 49^9_4Be + X → 48^8_4Be + Y needs X and Y to have the same Z, with Y one nucleon heavier.

  • (γ, n): 9+0=8+19+0=8+1, 4+0=4+04+0=4+0 ✓
  • (p, D): 9+1=8+29+1=8+2, 4+1=4+14+1=4+1 ✓
  • (n, D): Z: 4+0≠4+14+0\ne4+1 ✗
  • (γ, p): Z: 4≠4+14\ne4+1 ✗

(A), (B)