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← JEE Advanced 2013 · Paper 1
PhysicsMultiple correct+4 / -1Question 13 of 60

JEE Advanced 2013 · Paper 1, Physics question 13

A particle of mass MM and positive charge QQ, moving with a constant velocity u⃗1=4i^ m s−1\vec u_1=4\hat i\ \mathrm{m\,s^{-1}}, enters a region of uniform static magnetic field normal to the xx-yy plane. The region of the magnetic field extends from x=0x=0 to x=Lx=L for all values of yy. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity u⃗2=2(3i^+j^) m s−1\vec u_2=2\left(\sqrt3\hat i+\hat j\right)\ \mathrm{m\,s^{-1}}. The correct statement(s) is (are)

Choose one or more options
Answer and worked solution

Official answer: A, C

Direction. The velocity turns from +i^+\hat i towards +j^+\hat j, so at entry the force is along +j^+\hat j. With Q>0Q>0: i^×B⃗∝j^\hat i\times\vec B\propto\hat j requires B⃗\vec B along −z^-\hat z.

Magnitude. The velocity turns through 30° (π6\frac\pi6) in 10 ms, so ω=π/60.01=50π3\omega=\dfrac{\pi/6}{0.01}=\dfrac{50\pi}3 rad/s. Since ω=QBM\omega=\dfrac{QB}M,
B=50πM3Q.B=\frac{50\pi M}{3Q}.

(A), (C)