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← JEE Advanced 2013 · Paper 1
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JEE Advanced 2013 · Paper 1, Physics question 10

The image of an object, formed by a plano-convex lens at a distance of 8 m behind the lens, is real and is one-third the size of the object. The wavelength of light inside the lens is 23\dfrac23 times the wavelength in free space. The radius of the curved surface of the lens is

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Answer and worked solution

Official answer: C

Refractive index. μ=λ0λ=32\mu=\dfrac{\lambda_0}{\lambda}=\dfrac32.

Focal length. Real image one-third size: v=8v=8 m, u=−24u=-24 m. 1f=18+124=16\dfrac1f=\dfrac18+\dfrac1{24}=\dfrac16, so f=6f=6 m.

Plano-convex lens. 1f=μ−1R\dfrac1f=\dfrac{\mu-1}R, so R=0.5×6=3R=0.5\times6=3 m.

(C)