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← JEE Advanced 2013 · Paper 1
ChemistrySingle correct+2Question 28 of 60

JEE Advanced 2013 · Paper 1, Chemistry question 28

Consider the following complex ions, P, Q and R.
P=[FeFX6]X3−,Q=[V(HX2O)X6]X2+andR=[Fe(HX2O)X6]X2+.\mathbf P=\ce{[FeF6]^{3-}},\quad\mathbf Q=\ce{[V(H2O)6]^{2+}}\quad\text{and}\quad\mathbf R=\ce{[Fe(H2O)6]^{2+}}.
The correct order of the complex ions, according to their spin-only magnetic moment values (in B.M.) is

Choose one option
Answer and worked solution

Official answer: B

Unpaired electrons (water and F⁻ are weak-field):

  • P: Fe³⁺, d⁵ high spin, 5 unpaired, μ = 5.92 BM
  • Q: V²⁺, d³, 3 unpaired, μ = 3.87 BM
  • R: Fe²⁺, d⁶ high spin, 4 unpaired, μ = 4.90 BM

Order: Q < R < P.

(B)