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← IIT-JEE 2012 · Paper 2
ChemistrySingle correct+3 / -1Question 27 of 60

IIT-JEE 2012 · Paper 2, Chemistry question 27

Using the data provided, calculate the multiple bond energy (kJ mol⁻¹) of a C≡C bond in CX2HX2\ce{C2H2}. That energy is (take the bond energy of a C-H bond as 350 kJ mol⁻¹.)

2 C(s)+HX2(g)→CX2HX2(g)\ce{2C(s) + H2(g) -> C2H2(g)}, ΔH=225\Delta H=225 kJ mol⁻¹

2 C(s)→2 C(g)\ce{2C(s) -> 2C(g)}, ΔH=1410\Delta H=1410 kJ mol⁻¹

HX2(g)→2 H(g)\ce{H2(g) -> 2H(g)}, ΔH=330\Delta H=330 kJ mol⁻¹

Choose one option
Answer and worked solution

Official answer: D

Formation through atoms. Build CX2HX2\ce{C2H2} from gaseous atoms:
ΔHf=[ΔH(2 C(s)→2 C(g))+ΔH(HX2→2 H)]−[2EC−H+EC≡C].\Delta H_f=\left[\Delta H(\ce{2C(s)->2C(g)})+\Delta H(\ce{H2->2H})\right]-\left[2E_{\ce{C-H}}+E_{\ce{C#C}}\right].
225=1410+330−(700+EC≡C)  ⟹  EC≡C=815 kJ mol−1.225=1410+330-\left(700+E_{\ce{C#C}}\right)\implies E_{\ce{C#C}}=815\ \mathrm{kJ\,mol^{-1}}.

(D)