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← IIT-JEE 2012 · Paper 2
ChemistrySingle correct+3 / -1Question 24 of 60

IIT-JEE 2012 · Paper 2, Chemistry question 24

The shape of XeOX2FX2\ce{XeO2F2} molecule is

Choose one option
Answer and worked solution

Official answer: D

Electron pairs on Xe. Xe has 8 valence electrons. Two Xe=O bonds and two Xe-F bonds use 6 of them, leaving one lone pair. Five electron domains give a trigonal bipyramid.

Shape. The lone pair goes equatorial, so the atoms form a see-saw (the two F axial, the two O equatorial).

(D)