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← IIT-JEE 2011 · Paper 2
PhysicsInteger+4Question 35 of 60

IIT-JEE 2011 · Paper 2, Physics question 35

Two batteries of different emfs and different internal resistances are connected as shown. The voltage across AB in volts is

Two branches in parallel between A and B: upper branch a 6 V cell with 1 Ω, lower branch a 3 V cell with 2 Ω, both cells with the same polarity orientation.
Answer and worked solution

Official answer: 5

Two cells in parallel with like terminals together (positive towards A). Loop current I=6−31+2=1I=\dfrac{6-3}{1+2}=1 A.

Voltage. VAB=6−1×1=3+1×2=5V_{AB}=6-1\times1=3+1\times2=5 V. Equivalently V=6/1+3/21/1+1/2=5V=\dfrac{6/1+3/2}{1/1+1/2}=5 V.

Answer: 5