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← IIT-JEE 2011 · Paper 2
ChemistryMultiple correct+4Question 11 of 60

IIT-JEE 2011 · Paper 2, Chemistry question 11

For the first order reaction
2 NX2OX5(g)→4 NOX2(g)+OX2(g)\ce{2N2O5(g) -> 4NO2(g) + O2(g)}

Choose one or more options
Answer and worked solution

Official answer: A, B, D

First order: [A]=[A]0e−kt[A]=[A]_0e^{-kt} (A) and t1/2=0.693kt_{1/2}=\dfrac{0.693}k, independent of [A]0[A]_0 (C is false).

Temperature. kk rises with temperature (Arrhenius), so t1/2t_{1/2} falls (B).

Eight half-lives. Fraction left =2−8=1256=0.39%=2^{-8}=\frac1{256}=0.39\%, so 99.6% has reacted (D).

(A), (B), (D)