IIT-JEE 2011 · Paper 2, Chemistry question 8

Read the ring. A six-membered ring with one O (a pyranose), an exocyclic $\ce{CH2OH}$ and an OH on C-1 next to the ring O. Opening the ring gives an aldehyde at C-1, so the sugar is an aldohexose (glucose).

Anomer. All substituents, including the anomeric OH, are equatorial, so it is β-D-glucopyranose, not α. It is not a furanose and not a ketose.

(B)