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← IIT-JEE 2011 · Paper 1
PhysicsSingle correct+3 / -1Question 29 of 69

IIT-JEE 2011 · Paper 1, Physics question 29

A meter bridge is set-up as shown, to determine an unknown resistance 'X' using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of 'X' is

Metre bridge: X in the left gap and 10 Ω in the right gap; a cell across the ends; a galvanometer from the middle junction to a jockey on the wire AB (A on the left).
Choose one option
Answer and worked solution

Official answer: B

Corrected lengths. 52+1=5352+1=53 cm and 48+2=5048+2=50 cm.

Balance. X10=5350\dfrac X{10}=\dfrac{53}{50}, so X=10.6 ΩX=10.6\ \Omega.

(B)